1000:A+B

时间限制: 2 S | 内存限制: 65536 KB
Accept: 613 | Submit: 1306
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描述

calculate a+b.

输入

Two integer a, b. (0<=a, b<=10)

输出

Output a+b and line feed.

样例输入

1 2

样例输出

3


HINT

C++

#include "iostream"
using namespace std;
int main()
{
	int a, b;
	cin >> a >> b;
	cout << a + b << endl;
	return 0;
}
多组案例

while(cin >> a >> b)
{
	...
}
C

#include "stdio.h"
int main()
{
	int a,b;
	scanf("%d %d",&a, &b);
	printf("%d\n",a + b);
	return 0;
}
多组案例

while(scanf("%d%d", &a,&b) != EOF) // 或 while(~scanf("%d%d", &a,&b))
{
	...
}
JAVA(因语言特性 主类名统一取名 Main)禁用无关的类和方法

import java.io.*;
import java.util.*;
public class Main {
	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);
		int a = scanner.nextInt();
		int b = scanner.nextInt();
		System.out.println(a + b);
	}
}
多组案例

while(scanner.hasNextInt())
{
	int a = scanner.nextInt();
	int b = scanner.nextInt();
	...
}
Python2

a, b = (int(x) for x in raw_input().split())
print(a + b)
或者

print sum(map(int,raw_input().split()))
多组案例

while True:
	try:
		a, b = (int(x) for x in raw_input().split())
		...
	except:
		break
Python2的raw_input就是Python3的input

来源
POJ